4/5y+7/y-2

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Solution for 4/5y+7/y-2 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(4/5)*y+7/y-2 = 0

4/5*y^1+7*y^-1-2*y^0 = 0

(4/5*y^2-2*y^1+7*y^0)/(y^1) = 0 // * y^2

y^1*(4/5*y^2-2*y^1+7*y^0) = 0

y^1

(4/5)*y^2-2*y+7 = 0

(4/5)*y^2-2*y+7 = 0

DELTA = (-2)^2-(4*7*(4/5))

DELTA = -92/5

DELTA < 0

y in { }

y belongs to the empty set

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