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4/5y-1/2y=6
We move all terms to the left:
4/5y-1/2y-(6)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 2y!=0We calculate fractions
y!=0/2
y!=0
y∈R
8y/10y^2+(-5y)/10y^2-6=0
We multiply all the terms by the denominator
8y+(-5y)-6*10y^2=0
Wy multiply elements
-60y^2+8y+(-5y)=0
We get rid of parentheses
-60y^2+8y-5y=0
We add all the numbers together, and all the variables
-60y^2+3y=0
a = -60; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-60)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-60}=\frac{-6}{-120} =1/20 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-60}=\frac{0}{-120} =0 $
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