4/5y-3y=-3

Solution for 4/5y-3y=-3 equation:

4/5y-3y=-3

We move all terms to the left:

4/5y-3y-(-3)=0


Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R


We add all the numbers together, and all the variables

-3y+4/5y+3=0

We multiply all the terms by the denominator


-3y*5y+3*5y+4=0

Wy multiply elements

-15y^2+15y+4=0

a = -15; b = 15; c = +4;
Δ = b2-4ac
Δ = 152-4·(-15)·4
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{465}}{2*-15}=\frac{-15-\sqrt{465}}{-30}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{465}}{2*-15}=\frac{-15+\sqrt{465}}{-30}
$