4/5z+8=40

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Solution for 4/5z+8=40 equation: 



4/5z+8=40

We move all terms to the left:

4/5z+8-(40)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R



We add all the numbers together, and all the variables

4/5z-32=0

We multiply all the terms by the denominator


-32*5z+4=0

Wy multiply elements

-160z+4=0

We move all terms containing z to the left, all other terms to the right

-160z=-4

z=-4/-160

z=1/40

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