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4/5z-1/5z+1=3/5z+1
We move all terms to the left:
4/5z-1/5z+1-(3/5z+1)=0
Domain of the equation: 5z!=0
z!=0/5
z!=0
z∈R
Domain of the equation: 5z+1)!=0We get rid of parentheses
z∈R
4/5z-1/5z-3/5z-1+1=0
We multiply all the terms by the denominator
-1*5z+1*5z+4-1-3=0
We add all the numbers together, and all the variables
-1*5z+1*5z=0
Wy multiply elements
-5z+5z=0
We add all the numbers together, and all the variables
=0
z=0/1
z=0
Równanie nie ma rozwiązania
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