4/5z-5=19

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Solution for 4/5z-5=19 equation: 



4/5z-5=19

We move all terms to the left:

4/5z-5-(19)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R



We add all the numbers together, and all the variables

4/5z-24=0

We multiply all the terms by the denominator


-24*5z+4=0

Wy multiply elements

-120z+4=0

We move all terms containing z to the left, all other terms to the right

-120z=-4

z=-4/-120

z=1/30

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