4/7+3/5x=2+4/7x

Solution for 4/7+3/5x=2+4/7x equation:

4/7+3/5x=2+4/7x

We move all terms to the left:

4/7+3/5x-(2+4/7x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/5x-(4/7x+2)+4/7=0

We get rid of parentheses

3/5x-4/7x-2+4/7=0

We calculate fractions


1029x/1715x^2+(-20x)/1715x^2+20x/1715x^2-2=0

We multiply all the terms by the denominator


1029x+(-20x)+20x-2*1715x^2=0

We add all the numbers together, and all the variables

1049x+(-20x)-2*1715x^2=0

Wy multiply elements

-3430x^2+1049x+(-20x)=0

We get rid of parentheses

-3430x^2+1049x-20x=0

We add all the numbers together, and all the variables

-3430x^2+1029x=0

a = -3430; b = 1029; c = 0;
Δ = b2-4ac
Δ = 10292-4·(-3430)·0
Δ = 1058841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1058841}=1029$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1029)-1029}{2*-3430}=\frac{-2058}{-6860}
=3/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1029)+1029}{2*-3430}=\frac{0}{-6860}
=0
$