4/7-2/n-3/n

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Solution for 4/7-2/n-3/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4/7-(2/n)-(3/n) = 0

4/7-2*n^-1-3*n^-1 = 0

-5*n^-1 = -4/7 // : -5

n^-1 = 4/35

-1 < 0

1/(n^1) = 4/35 // * n^1

1 = 4/35*n^1 // : 4/35

35/4 = n^1

n = 35/4

n = 35/4

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