4/7m+1/4m=24

Solution for 4/7m+1/4m=24 equation:

4/7m+1/4m=24

We move all terms to the left:

4/7m+1/4m-(24)=0


Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We calculate fractions


16m/28m^2+7m/28m^2-24=0

We multiply all the terms by the denominator


16m+7m-24*28m^2=0

We add all the numbers together, and all the variables

23m-24*28m^2=0

Wy multiply elements

-672m^2+23m=0

a = -672; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-672)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-672}=\frac{-46}{-1344}
=23/672
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-672}=\frac{0}{-1344}
=0
$