4/7m-6=1/3m+4

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Solution for 4/7m-6=1/3m+4 equation:



4/7m-6=1/3m+4
We move all terms to the left:
4/7m-6-(1/3m+4)=0
Domain of the equation: 7m!=0
m!=0/7
m!=0
m∈R
Domain of the equation: 3m+4)!=0
m∈R
We get rid of parentheses
4/7m-1/3m-4-6=0
We calculate fractions
12m/21m^2+(-7m)/21m^2-4-6=0
We add all the numbers together, and all the variables
12m/21m^2+(-7m)/21m^2-10=0
We multiply all the terms by the denominator
12m+(-7m)-10*21m^2=0
Wy multiply elements
-210m^2+12m+(-7m)=0
We get rid of parentheses
-210m^2+12m-7m=0
We add all the numbers together, and all the variables
-210m^2+5m=0
a = -210; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-210)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-210}=\frac{-10}{-420} =1/42 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-210}=\frac{0}{-420} =0 $

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