4/7m=2/7(2m+1

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Solution for 4/7m=2/7(2m+1 equation: 



4/7m=2/7(2m+1

We move all terms to the left:

4/7m-(2/7(2m+1)=0



Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R





Domain of the equation: 7(2m+1)!=0

m∈R



We calculate fractions


(28m2/(49m^22+(-(2*7m)/(49m^22=0

We do not support empression: m^22

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