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4/7x+1/3x=57
We move all terms to the left:
4/7x+1/3x-(57)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
12x/21x^2+7x/21x^2-57=0
We multiply all the terms by the denominator
12x+7x-57*21x^2=0
We add all the numbers together, and all the variables
19x-57*21x^2=0
Wy multiply elements
-1197x^2+19x=0
a = -1197; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-1197)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-1197}=\frac{-38}{-2394} =1/63 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-1197}=\frac{0}{-2394} =0 $
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