4/7x+5/18x=39

Solution for 4/7x+5/18x=39 equation:

4/7x+5/18x=39

We move all terms to the left:

4/7x+5/18x-(39)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 18x!=0

x!=0/18

x!=0

x∈R


We calculate fractions


72x/126x^2+35x/126x^2-39=0

We multiply all the terms by the denominator


72x+35x-39*126x^2=0

We add all the numbers together, and all the variables

107x-39*126x^2=0

Wy multiply elements

-4914x^2+107x=0

a = -4914; b = 107; c = 0;
Δ = b2-4ac
Δ = 1072-4·(-4914)·0
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(107)-107}{2*-4914}=\frac{-214}{-9828}
=107/4914
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(107)+107}{2*-4914}=\frac{0}{-9828}
=0
$