4/7x-5/3=(3x+1)/2

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Solution for 4/7x-5/3=(3x+1)/2 equation: 



4/7x-5/3=(3x+1)/2

We move all terms to the left:

4/7x-5/3-((3x+1)/2)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We calculate fractions


(-((3x+1)*7x*3)/42x^2+(-140x^2)/42x^2+()/42x^2=0

We can not solve this equation

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