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4/9(x+36)=-1/3(2x-18)
We move all terms to the left:
4/9(x+36)-(-1/3(2x-18))=0
Domain of the equation: 9(x+36)!=0
x∈R
Domain of the equation: 3(2x-18))!=0We calculate fractions
x∈R
(12x2/(9(x+36)*3(2x-18)))+(-(-9xx)/(9(x+36)*3(2x-18)))=0
We calculate terms in parentheses: +(12x2/(9(x+36)*3(2x-18))), so:
12x2/(9(x+36)*3(2x-18))
We multiply all the terms by the denominator
12x2
We add all the numbers together, and all the variables
12x^2
Back to the equation:
+(12x^2)
We calculate terms in parentheses: +(-(-9xx)/(9(x+36)*3(2x-18))), so:
-(-9xx)/(9(x+36)*3(2x-18))
We multiply all the terms by the denominator
-(-9xx)
We get rid of parentheses
9xx
Back to the equation:
+(9xx)
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