4/9(x-2)+5/7=1/7(x+3)

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Solution for 4/9(x-2)+5/7=1/7(x+3) equation: 



4/9(x-2)+5/7=1/7(x+3)

We move all terms to the left:

4/9(x-2)+5/7-(1/7(x+3))=0



Domain of the equation: 9(x-2)!=0

x∈R





Domain of the equation: 7(x+3))!=0

x∈R



We calculate fractions


(196xx/(9(x-2)*7(x+3))*7)+(-9xx/(9(x-2)*7(x+3))*7)+(45xx/(9(x-2)*7(x+3))*7)=0



We calculate terms in parentheses: +(196xx/(9(x-2)*7(x+3))*7), so:

196xx/(9(x-2)*7(x+3))*7

We multiply all the terms by the denominator


196xx

Back to the equation:

+(196xx)





We calculate terms in parentheses: +(-9xx/(9(x-2)*7(x+3))*7), so:

-9xx/(9(x-2)*7(x+3))*7

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)





We calculate terms in parentheses: +(45xx/(9(x-2)*7(x+3))*7), so:

45xx/(9(x-2)*7(x+3))*7

We multiply all the terms by the denominator


45xx

Back to the equation:

+(45xx)



We get rid of parentheses

196xx-9xx+45xx=0

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