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4/9x+1/5x=(87)
We move all terms to the left:
4/9x+1/5x-((87))=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 5x!=0determiningTheFunctionDomain 4/9x+1/5x-87=0
x!=0/5
x!=0
x∈R
We calculate fractions
20x/45x^2+9x/45x^2-87=0
We multiply all the terms by the denominator
20x+9x-87*45x^2=0
We add all the numbers together, and all the variables
29x-87*45x^2=0
Wy multiply elements
-3915x^2+29x=0
a = -3915; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-3915)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-3915}=\frac{-58}{-7830} =1/135 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-3915}=\frac{0}{-7830} =0 $
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