4/9x+6-1/3x=4

Solution for 4/9x+6-1/3x=4 equation:

4/9x+6-1/3x=4

We move all terms to the left:

4/9x+6-1/3x-(4)=0


Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

4/9x-1/3x+2=0

We calculate fractions


12x/27x^2+(-9x)/27x^2+2=0

We multiply all the terms by the denominator


12x+(-9x)+2*27x^2=0

Wy multiply elements

54x^2+12x+(-9x)=0

We get rid of parentheses

54x^2+12x-9x=0

We add all the numbers together, and all the variables

54x^2+3x=0

a = 54; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·54·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*54}=\frac{-6}{108}
=-1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*54}=\frac{0}{108}
=0
$