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4/9x+95=x
We move all terms to the left:
4/9x+95-(x)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
-1x+4/9x+95=0
We multiply all the terms by the denominator
-1x*9x+95*9x+4=0
Wy multiply elements
-9x^2+855x+4=0
a = -9; b = 855; c = +4;
Δ = b2-4ac
Δ = 8552-4·(-9)·4
Δ = 731169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{731169}=\sqrt{9*81241}=\sqrt{9}*\sqrt{81241}=3\sqrt{81241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(855)-3\sqrt{81241}}{2*-9}=\frac{-855-3\sqrt{81241}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(855)+3\sqrt{81241}}{2*-9}=\frac{-855+3\sqrt{81241}}{-18} $
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