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4/9x-1/2x=51
We move all terms to the left:
4/9x-1/2x-(51)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
8x/18x^2+(-9x)/18x^2-51=0
We multiply all the terms by the denominator
8x+(-9x)-51*18x^2=0
Wy multiply elements
-918x^2+8x+(-9x)=0
We get rid of parentheses
-918x^2+8x-9x=0
We add all the numbers together, and all the variables
-918x^2-1x=0
a = -918; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-918)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-918}=\frac{0}{-1836} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-918}=\frac{2}{-1836} =-1/918 $
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