4/a+5/3a=3

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Solution for 4/a+5/3a=3 equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

(5/3)*a+4/a = 3 // - 3

(5/3)*a+4/a-3 = 0

5/3*a^1+4*a^-1-3*a^0 = 0

(5/3*a^2-3*a^1+4*a^0)/(a^1) = 0 // * a^2

a^1*(5/3*a^2-3*a^1+4*a^0) = 0

a^1

(5/3)*a^2-3*a+4 = 0

(5/3)*a^2-3*a+4 = 0

DELTA = (-3)^2-(4*4*(5/3))

DELTA = -53/3

DELTA < 0

a in { } 

a belongs to the empty set

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