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4/a-1/5a=3
We move all terms to the left:
4/a-1/5a-(3)=0
Domain of the equation: a!=0
a∈R
Domain of the equation: 5a!=0We calculate fractions
a!=0/5
a!=0
a∈R
20a/5a^2+(-a)/5a^2-3=0
We add all the numbers together, and all the variables
20a/5a^2+(-1a)/5a^2-3=0
We multiply all the terms by the denominator
20a+(-1a)-3*5a^2=0
Wy multiply elements
-15a^2+20a+(-1a)=0
We get rid of parentheses
-15a^2+20a-1a=0
We add all the numbers together, and all the variables
-15a^2+19a=0
a = -15; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-15)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-15}=\frac{-38}{-30} =1+4/15 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-15}=\frac{0}{-30} =0 $
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