4/b+3/8b=5

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Solution for 4/b+3/8b=5 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

(3/8)*b+4/b = 5 // - 5

(3/8)*b+4/b-5 = 0

3/8*b^1+4*b^-1-5*b^0 = 0

(3/8*b^2-5*b^1+4*b^0)/(b^1) = 0 // * b^2

b^1*(3/8*b^2-5*b^1+4*b^0) = 0

b^1

(3/8)*b^2-5*b+4 = 0

(3/8)*b^2-5*b+4 = 0

DELTA = (-5)^2-(4*4*(3/8))

DELTA = 19

DELTA > 0

b = (19^(1/2)+5)/(2*(3/8)) or b = (5-19^(1/2))/(2*(3/8))

b = 4/3*(19^(1/2)+5) or b = 4/3*(5-19^(1/2))

b in { 4/3*(5-19^(1/2)), 4/3*(19^(1/2)+5)} 

b in { 4/3*(5-19^(1/2)), 4/3*(19^(1/2)+5) }

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