4/d+3=7/2d

Solution for 4/d+3=7/2d equation:

4/d+3=7/2d

We move all terms to the left:

4/d+3-(7/2d)=0


Domain of the equation: d!=0

d∈R



Domain of the equation: 2d)!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

4/d-(+7/2d)+3=0

We get rid of parentheses

4/d-7/2d+3=0

We calculate fractions


8d/2d^2+(-7d)/2d^2+3=0

We multiply all the terms by the denominator


8d+(-7d)+3*2d^2=0

Wy multiply elements

6d^2+8d+(-7d)=0

We get rid of parentheses

6d^2+8d-7d=0

We add all the numbers together, and all the variables

6d^2+d=0

a = 6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·6·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*6}=\frac{-2}{12}
=-1/6
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*6}=\frac{0}{12}
=0
$