4/k*2-8k+12=k/k-2+1/k-6

Solution for 4/k*2-8k+12=k/k-2+1/k-6 equation:

D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

2*(4/k)-(8*k)+12 = 1/k+k/k-6-2 // - 1/k+k/k-6-2

2*(4/k)-(8*k)-(1/k)-(k/k)+2+6+12 = 0

2*(4/k)-8*k-k^-1-1+2+6+12 = 0

7*k^-1-8*k^1+19*k^0 = 0

(19*k^1-8*k^2+7*k^0)/(k^1) = 0 // * k^2

k^1*(19*k^1-8*k^2+7*k^0) = 0

k^1

19*k-8*k^2+7 = 0

19*k-8*k^2+7 = 0

DELTA = 19^2-(-8*4*7)

DELTA = 585

DELTA > 0

k = (585^(1/2)-19)/(-8*2) or k = (-585^(1/2)-19)/(-8*2)

k = (3*65^(1/2)-19)/(-16) or k = (-3*65^(1/2)-19)/(-16)

k in { (3*65^(1/2)-19)/(-16), (-3*65^(1/2)-19)/(-16)} 

k in { (3*65^(1/2)-19)/(-16), (-3*65^(1/2)-19)/(-16) }