4/m+2+2m-2

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Solution for 4/m+2+2m-2 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

2*m+4/m-2+2 = 0

2*m^1+4*m^-1 = 0

(2*m^2+4*m^0)/(m^1) = 0 // * m^2

m^1*(2*m^2+4*m^0) = 0

m^1

2*m^2+4 = 0

2*m^2+4 = 0

DELTA = 0^2-(2*4*4)

DELTA = -32

DELTA < 0

m in { } 

m belongs to the empty set

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