4/n+3-3/w+2=0

Solution for 4/n+3-3/w+2=0 equation:

4/+3-3/N+2=0


Domain of the equation: N!=0

N∈R


We add all the numbers together, and all the variables

-3/N+5+4/=0

We calculate fractions


()/(N*)+4N/(N*)+5=0

We add all the numbers together, and all the variables

()/(+N*)+4N/(+N*)+5=0

We multiply all the terms by the denominator


4N+5*(+N*)+()=0

We add all the numbers together, and all the variables

4N+5*(+N*)=0

We multiply parentheses

5N^2+4N=0

a = 5; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·5·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*5}=\frac{-8}{10}
=-4/5
$
$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*5}=\frac{0}{10}
=0
$