4/n=5/2n+3

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Solution for 4/n=5/2n+3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4/n = (5/2)*n+3 // - (5/2)*n+3

4/n-((5/2)*n)-3 = 0

(-5/2)*n+4/n-3 = 0

4*n^-1-5/2*n^1-3*n^0 = 0

(4*n^0-5/2*n^2-3*n^1)/(n^1) = 0 // * n^2

n^1*(4*n^0-5/2*n^2-3*n^1) = 0

n^1

(-5/2)*n^2-3*n+4 = 0

(-5/2)*n^2-3*n+4 = 0

DELTA = (-3)^2-(4*4*(-5/2))

DELTA = 49

DELTA > 0

n = (49^(1/2)+3)/(2*(-5/2)) or n = (3-49^(1/2))/(2*(-5/2))

n = -2 or n = 4/5

n in { -2, 4/5} 

n in { -2, 4/5 }

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