4/n=6/2n-3

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Solution for 4/n=6/2n-3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4/n = (6/2)*n-3 // - (6/2)*n-3

4/n-((6/2)*n)+3 = 0

4/n-3*n+3 = 0

4*n^-1-3*n^1+3*n^0 = 0

(3*n^1-3*n^2+4*n^0)/(n^1) = 0 // * n^2

n^1*(3*n^1-3*n^2+4*n^0) = 0

n^1

3*n-3*n^2+4 = 0

3*n-3*n^2+4 = 0

DELTA = 3^2-(-3*4*4)

DELTA = 57

DELTA > 0

n = (57^(1/2)-3)/(-3*2) or n = (-57^(1/2)-3)/(-3*2)

n = (57^(1/2)-3)/(-6) or n = (57^(1/2)+3)/6

n in { (57^(1/2)-3)/(-6), (57^(1/2)+3)/6} 

n in { (57^(1/2)-3)/(-6), (57^(1/2)+3)/6 }

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