4/r-1/2=5/12-3/2r

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Solution for 4/r-1/2=5/12-3/2r equation:


D( r )

r = 0

r = 0

r = 0

r in (-oo:0) U (0:+oo)

4/r-(1/2) = 5/12-((3/2)*r) // - 5/12-((3/2)*r)

(3/2)*r+4/r-(1/2)-(5/12) = 0

(3/2)*r+4/r-1/2-5/12 = 0

3/2*r^1+4*r^-1-11/12*r^0 = 0

(3/2*r^2-11/12*r^1+4*r^0)/(r^1) = 0 // * r^2

r^1*(3/2*r^2-11/12*r^1+4*r^0) = 0

r^1

(3/2)*r^2+(-11/12)*r+4 = 0

(3/2)*r^2+(-11/12)*r+4 = 0

DELTA = (-11/12)^2-(4*4*(3/2))

DELTA = -3335/144

DELTA < 0

r in { }

r belongs to the empty set

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