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4/w-12=2/3w
We move all terms to the left:
4/w-12-(2/3w)=0
Domain of the equation: w!=0
w∈R
Domain of the equation: 3w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
4/w-(+2/3w)-12=0
We get rid of parentheses
4/w-2/3w-12=0
We calculate fractions
12w/3w^2+(-2w)/3w^2-12=0
We multiply all the terms by the denominator
12w+(-2w)-12*3w^2=0
Wy multiply elements
-36w^2+12w+(-2w)=0
We get rid of parentheses
-36w^2+12w-2w=0
We add all the numbers together, and all the variables
-36w^2+10w=0
a = -36; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-36)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-36}=\frac{-20}{-72} =5/18 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-36}=\frac{0}{-72} =0 $
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