4/x+1+6/3x+1=15/3x+1

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Solution for 4/x+1+6/3x+1=15/3x+1 equation: 



4/x+1+6/3x+1=15/3x+1

We move all terms to the left:

4/x+1+6/3x+1-(15/3x+1)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x+1)!=0

x∈R



We add all the numbers together, and all the variables

4/x+6/3x-(15/3x+1)+2=0

We get rid of parentheses

4/x+6/3x-15/3x-1+2=0

We calculate fractions


12x/3x^2+(-15x+6)/3x^2-1+2=0

We add all the numbers together, and all the variables

12x/3x^2+(-15x+6)/3x^2+1=0

We multiply all the terms by the denominator


12x+(-15x+6)+1*3x^2=0

Wy multiply elements

3x^2+12x+(-15x+6)=0

We get rid of parentheses

3x^2+12x-15x+6=0

We add all the numbers together, and all the variables

3x^2-3x+6=0

a = 3; b = -3; c = +6;
Δ = b2-4ac
Δ = -32-4·3·6
Δ = -63
Delta is less than zero, so there is no solution for the equation

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