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4/x+12/(x+3)=-13
We move all terms to the left:
4/x+12/(x+3)-(-13)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
4/x+12/(x+3)+13=0
We calculate fractions
(4x+12)/(x^2+3x)+12x/(x^2+3x)+13=0
We multiply all the terms by the denominator
(4x+12)+12x+13*(x^2+3x)=0
We add all the numbers together, and all the variables
12x+(4x+12)+13*(x^2+3x)=0
We multiply parentheses
13x^2+12x+(4x+12)+39x=0
We get rid of parentheses
13x^2+12x+4x+39x+12=0
We add all the numbers together, and all the variables
13x^2+55x+12=0
a = 13; b = 55; c = +12;
Δ = b2-4ac
Δ = 552-4·13·12
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-49}{2*13}=\frac{-104}{26} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+49}{2*13}=\frac{-6}{26} =-3/13 $
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