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4/x+1=5/3x+1
We move all terms to the left:
4/x+1-(5/3x+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+1)!=0We get rid of parentheses
x∈R
4/x-5/3x-1+1=0
We calculate fractions
12x/3x^2+(-5x)/3x^2-1+1=0
We add all the numbers together, and all the variables
12x/3x^2+(-5x)/3x^2=0
We multiply all the terms by the denominator
12x+(-5x)=0
We get rid of parentheses
12x-5x=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
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