4/x+2=-7/2x+4+1

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Solution for 4/x+2=-7/2x+4+1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+2 = (-7/2)*x+1+4 // - (-7/2)*x+1+4

4/x-((-7/2)*x)-4-1+2 = 0

(7/2)*x+4/x-4-1+2 = 0

7/2*x^1+4*x^-1-3*x^0 = 0

(7/2*x^2-3*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(7/2*x^2-3*x^1+4*x^0) = 0

x^1

(7/2)*x^2-3*x+4 = 0

(7/2)*x^2-3*x+4 = 0

DELTA = (-3)^2-(4*4*(7/2))

DELTA = -47

DELTA < 0

x in { } 

x belongs to the empty set

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