4/x+2=7/2x-3

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Solution for 4/x+2=7/2x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+2 = (7/2)*x-3 // - (7/2)*x-3

4/x-((7/2)*x)+2+3 = 0

(-7/2)*x+4/x+2+3 = 0

4*x^-1-7/2*x^1+5*x^0 = 0

(5*x^1-7/2*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^1-7/2*x^2+4*x^0) = 0

x^1

(-7/2)*x^2+5*x+4 = 0

(-7/2)*x^2+5*x+4 = 0

DELTA = 5^2-(4*4*(-7/2))

DELTA = 81

DELTA > 0

x = (81^(1/2)-5)/(2*(-7/2)) or x = (-81^(1/2)-5)/(2*(-7/2))

x = -4/7 or x = 2

x in { -4/7, 2} 

x in { -4/7, 2 }

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