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4/x+3)-(3/x-3)=7/3
We move all terms to the left:
4/x+3)-(3/x-3)-(7/3)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
4/x+3)-(3/x-3)-(+7/3)=0
We add all the numbers together, and all the variables
4/x+3)-(3/x+7/3)=0
We calculate fractions
()/3x^2+7x/3x^2=0
We multiply all the terms by the denominator
7x+()=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
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