4/x+3+5/2x-1

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Solution for 4/x+3+5/2x-1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/2)*x+4/x-1+3 = 0

5/2*x^1+4*x^-1+2*x^0 = 0

(5/2*x^2+2*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2+2*x^1+4*x^0) = 0

x^1

(5/2)*x^2+2*x+4 = 0

(5/2)*x^2+2*x+4 = 0

DELTA = 2^2-(4*4*(5/2))

DELTA = -36

DELTA < 0

x in { } 

x belongs to the empty set

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