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4/x+4-2/4x+16=15
We move all terms to the left:
4/x+4-2/4x+16-(15)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
4/x-2/4x+5=0
We calculate fractions
16x/4x^2+(-2x)/4x^2+5=0
We multiply all the terms by the denominator
16x+(-2x)+5*4x^2=0
Wy multiply elements
20x^2+16x+(-2x)=0
We get rid of parentheses
20x^2+16x-2x=0
We add all the numbers together, and all the variables
20x^2+14x=0
a = 20; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·20·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*20}=\frac{-28}{40} =-7/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*20}=\frac{0}{40} =0 $
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