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4/x+4/3x=x/3
We move all terms to the left:
4/x+4/3x-(x/3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4/x+4/3x-(+x/3)=0
We get rid of parentheses
4/x+4/3x-x/3=0
We calculate fractions
(-1x^2)/27x^2+108x/27x^2+4x/27x^2=0
We multiply all the terms by the denominator
(-1x^2)+108x+4x=0
We add all the numbers together, and all the variables
(-1x^2)+112x=0
We get rid of parentheses
-1x^2+112x=0
a = -1; b = 112; c = 0;
Δ = b2-4ac
Δ = 1122-4·(-1)·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-112}{2*-1}=\frac{-224}{-2} =+112 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+112}{2*-1}=\frac{0}{-2} =0 $
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