4/x+6=8/3x+5

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Solution for 4/x+6=8/3x+5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+6 = (8/3)*x+5 // - (8/3)*x+5

4/x-((8/3)*x)-5+6 = 0

(-8/3)*x+4/x-5+6 = 0

4*x^-1-8/3*x^1+1*x^0 = 0

(1*x^1-8/3*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^1-8/3*x^2+4*x^0) = 0

x^1

(-8/3)*x^2+x+4 = 0

(-8/3)*x^2+x+4 = 0

DELTA = 1^2-(4*4*(-8/3))

DELTA = 131/3

DELTA > 0

x = ((131/3)^(1/2)-1)/(2*(-8/3)) or x = (-(131/3)^(1/2)-1)/(2*(-8/3))

x = -3/16*((131/3)^(1/2)-1) or x = 3/16*((131/3)^(1/2)+1)

x in { -3/16*((131/3)^(1/2)-1), 3/16*((131/3)^(1/2)+1)} 

x in { -3/16*((131/3)^(1/2)-1), 3/16*((131/3)^(1/2)+1) }

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