4/x-1+6/3x+1=15/3x+1

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Solution for 4/x-1+6/3x+1=15/3x+1 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(6/3)*x+4/x-1+1 = (15/3)*x+1 // - (15/3)*x+1

(6/3)*x-((15/3)*x)+4/x-1-1+1 = 0

(6/3)*x-5*x+4/x-1-1+1 = 0

4*x^-1-3*x^1-1*x^0 = 0

(4*x^0-3*x^2-1*x^1)/(x^1) = 0 // * x^2

x^1*(4*x^0-3*x^2-1*x^1) = 0

x^1

4-3*x^2-x = 0

4-3*x^2-x = 0

DELTA = (-1)^2-(-3*4*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+1)/(-3*2) or x = (1-49^(1/2))/(-3*2)

x = -4/3 or x = 1

x in { -4/3, 1}

x in { -4/3, 1 }

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