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4/x-5=5/2x
We move all terms to the left:
4/x-5-(5/2x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4/x-(+5/2x)-5=0
We get rid of parentheses
4/x-5/2x-5=0
We calculate fractions
8x/2x^2+(-5x)/2x^2-5=0
We multiply all the terms by the denominator
8x+(-5x)-5*2x^2=0
Wy multiply elements
-10x^2+8x+(-5x)=0
We get rid of parentheses
-10x^2+8x-5x=0
We add all the numbers together, and all the variables
-10x^2+3x=0
a = -10; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-10)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-10}=\frac{-6}{-20} =3/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-10}=\frac{0}{-20} =0 $
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