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4/x=12/(2x+5)
We move all terms to the left:
4/x-(12/(2x+5))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (2x+5))!=0We calculate fractions
x∈R
8x/7x^2+(-(12*x)/7x^2=0
We add all the numbers together, and all the variables
8x/7x^2+(-(+12x)/7x^2=0
We multiply all the terms by the denominator
8x+(-(+12x)=0
We calculate terms in parentheses: +(-(+12x), so:
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We calculate terms in parentheses: +(-(+12x), so:
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We calculate terms in parentheses: +(-(+12x), so:
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We calculate terms in parentheses: +(-(+12x), so:
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| X-3/x-6=2 | | 9m-12=87 | | 2.5x+6=1.25 | | x-x/10=-11 | | c=1500/2+300-25(2)+1.5(6) | | 3/4x+5/8x=2 | | 4(2.5-x)-4.5=12.5 | | 100=30x+0.25 | | c=1500/2+300-25(2)+1.5(4) | | 100=0.25x+30 | | 10x=7.9 | | 225=-16t^2-32t+225 | | 2x^2+15=35 | | .75x+5=1 | | 2x+5/3=X-1/5 | | -4+2x=17-x | | v=6v−5v | | x-89=578 | | x/7=x+3/8 | | 254r=-49 | | 89-x=578 | | 3j−6=3j | | 15.6+5y=9y+4 | | -4(x+3)=5x-1 | | 4w+-22=9w+3 | | 3u+19=6u-5 | | 13+15x=20+7x | | 5x=(2÷4)^2 | | 34-(3c+4)=2c+6+6 | | m-5=15,m= | | 9x-10x+7=9 | | –7h=–h−6h |