4/x=9/5-7x-4/5x

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Solution for 4/x=9/5-7x-4/5x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x = 9/5-(7*x)-((4/5)*x) // - 9/5-(7*x)-((4/5)*x)

7*x+(4/5)*x+4/x-(9/5) = 0

7*x+(4/5)*x+4/x-9/5 = 0

39/5*x^1+4*x^-1-9/5*x^0 = 0

(39/5*x^2-9/5*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(39/5*x^2-9/5*x^1+4*x^0) = 0

x^1

(39/5)*x^2+(-9/5)*x+4 = 0

(39/5)*x^2+(-9/5)*x+4 = 0

DELTA = (-9/5)^2-(4*4*(39/5))

DELTA = -3039/25

DELTA < 0

x in { } 

x belongs to the empty set

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