4/y+1/3=7/3y

Solution for 4/y+1/3=7/3y equation:

D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

4/y+1/3 = (7/3)*y // - (7/3)*y

4/y-((7/3)*y)+1/3 = 0

(-7/3)*y+4/y+1/3 = 0

4*y^-1-7/3*y^1+1/3*y^0 = 0

(1/3*y^1-7/3*y^2+4*y^0)/(y^1) = 0 // * y^2

y^1*(1/3*y^1-7/3*y^2+4*y^0) = 0

y^1

(-7/3)*y^2+(1/3)*y+4 = 0

(-7/3)*y^2+(1/3)*y+4 = 0

DELTA = (1/3)^2-(4*4*(-7/3))

DELTA = 337/9

DELTA > 0

y = ((337/9)^(1/2)-(1/3))/(2*(-7/3)) or y = (-(1/3)-(337/9)^(1/2))/(2*(-7/3))

y = -3/14*((337/9)^(1/2)-1/3) or y = 3/14*((337/9)^(1/2)+1/3)

y in { -3/14*((337/9)^(1/2)-1/3), 3/14*((337/9)^(1/2)+1/3)} 

y in { -3/14*((337/9)^(1/2)-1/3), 3/14*((337/9)^(1/2)+1/3) }