4/y+2+y-2/y+2+2=-2

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Solution for 4/y+2+y-2/y+2+2=-2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+4/y-(2/y)+2+2+2 = -2 // + 2

y+4/y-(2/y)+2+2+2+2 = 0

y+4/y-2*y^-1+2+2+2+2 = 0

1*y^1+2*y^-1+8*y^0 = 0

(1*y^2+8*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2+8*y^1+2*y^0) = 0

y^1

y^2+8*y+2 = 0

y^2+8*y+2 = 0

DELTA = 8^2-(1*2*4)

DELTA = 56

DELTA > 0

y = (56^(1/2)-8)/(1*2) or y = (-56^(1/2)-8)/(1*2)

y = (2*14^(1/2)-8)/2 or y = (-2*14^(1/2)-8)/2

y in { (-2*14^(1/2)-8)/2, (2*14^(1/2)-8)/2} 

y in { (-2*14^(1/2)-8)/2, (2*14^(1/2)-8)/2 }

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