4/y+y=2y

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Solution for 4/y+y=2y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+4/y = 2*y // - 2*y

y-(2*y)+4/y = 0

y-2*y+4/y = 0

4*y^-1-1*y^1 = 0

(4*y^0-1*y^2)/(y^1) = 0 // * y^2

y^1*(4*y^0-1*y^2) = 0

y^1

4-y^2 = 0

4-y^2 = 0

DELTA = 0^2-(-1*4*4)

DELTA = 16

DELTA > 0

y = (16^(1/2)+0)/(-1*2) or y = (0-16^(1/2))/(-1*2)

y = -2 or y = 2

y in { -2, 2} 

y in { -2, 2 }

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