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4/z+1/z=2/(2+3)
We move all terms to the left:
4/z+1/z-(2/(2+3))=0
Domain of the equation: z!=0We add all the numbers together, and all the variables
z∈R
4/z+1/z-(2/5)=0
We get rid of parentheses
4/z+1/z-2/5=0
We calculate fractions
There is no solution for this equation
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