4/z+1/z=2/(z+3)

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Solution for 4/z+1/z=2/(z+3) equation: 


D( z )

z+3 = 0

z = 0

z+3 = 0

z+3 = 0

z+3 = 0 // - 3

z = -3

z = 0

z = 0

z in (-oo:-3) U (-3:0) U (0:+oo)

4/z+1/z = 2/(z+3) // - 2/(z+3)

4/z-(2/(z+3))+1/z = 0

4/z-2*(z+3)^-1+1/z = 0

4/z-2/(z+3)+1/z = 0

(-2*z)/(z*(z+3))+(4*(z+3))/(z*(z+3))+(1*(z+3))/(z*(z+3)) = 0

4*(z+3)+1*(z+3)-2*z = 0

2*z+z+3+12 = 0

3*z+15 = 0

(3*z+15)/(z*(z+3)) = 0

(3*z+15)/(z*(z+3)) = 0 // * z*(z+3)

3*z+15 = 0

3*z+15 = 0 // - 15

3*z = -15 // : 3

z = -15/3

z = -5

z = -5

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